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It turns out one of my favorite newer West Wing characters, Elsie Snuffin, who I think of as "Will's smarter sister", is a math geek in real life, with a published proof to her credit. She even has a math section on her official fan site, where she answers fan's questions with discursive, tutorial-style answers.

Q: I think you are great on "The West Wing"! Here’s my current problem, it’s in advanced finite math (I’m a high school senior): At the height of the Beatles’ popularity, it was estimated that every popular music station played their music 40% of the time. If you tuned through 10 such stations at any given moment, what is the probability that at least *one* of the stations would be playing a Beatles song? Thanks!

Danica Answers: A probability question! Okay, lets call "x" the probability that "at least one of the 10 stations would be playing a Beatles song at that moment." Thats what were asked to find. Then lets call "y" the probability that "none of those 10 stations would be playing a Beatles song at that moment." Notice that x+y = 1.... Okay, so well now determine the value of "y" which is much easier than going through all the necessary calculations required to determine "x" directly. This is a common strategy in probability....

I am so amused.

Date: 2005-07-21 12:45 am (UTC)
From: [identity profile] ocschwar.livejournal.com
Note she is among two people who have both an Erdos number and a Bacon number (the other being Erdos).

Date: 2005-07-21 01:06 am (UTC)
From: [identity profile] goldsquare.livejournal.com
If there is even a single connector between the two graphs, wouldn't everyone in both graphs have a Erdos and Bacon #? (Well, we all do - if zero counts.)

Date: 2005-07-21 01:09 am (UTC)
From: [identity profile] ocschwar.livejournal.com
I'm not sure how much has been written about graphs whose connections are divided among two or more classes that are not treated equivalently, but mathematicians do ponder everything so someone must have..

Date: 2005-07-21 01:39 am (UTC)
From: [identity profile] goldsquare.livejournal.com
Well, think about it. If I had a Bacon number of 4, and it was a Bacon number of 2 to Danica McKellar, and she had an Erdos number of 2... it is 4 steps to Bacon plus 2 to Danica plus 2 to Erdos. And I'd have an Erdos number of 8.

Of course, that is a bit silly, now that I think about it, since I am obviously wrong. The only way to get an Erdos number is to write a mathematical paper, and the only way to get a Bacon number is to star in a movie.

You can't connect the graphs in a meaningful way.

Date: 2005-07-25 11:39 pm (UTC)
From: [identity profile] herooftheage.livejournal.com
Uhm, only Erdos has an Erdos number of 0. If you've never co-authored a paper with anyone, your Erdos # is infinite. I think it's an open question as to whether more people have infinite Erdos numbers or infinite Bacon numbers.

Date: 2005-07-26 02:25 pm (UTC)
From: [identity profile] goldsquare.livejournal.com
Good points. Thanks.

Date: 2005-07-21 03:19 am (UTC)
coraline: (Default)
From: [personal profile] coraline
...i was about to retort that the woman who played "winnie" on "the wonder years" also had one... and then i did my research and found out it was the same actress.
figures it would be too much to hope for for there to be ANOTHER famous actress quite that math-geeky.

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